(5x-5)/(x^2-9)=(7x)/(x^2-9)

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Solution for (5x-5)/(x^2-9)=(7x)/(x^2-9) equation: 


D( x )

x^2-9 = 0

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(5*x-5)/(x^2-9) = (7*x)/(x^2-9) // - (7*x)/(x^2-9)

(5*x-5)/(x^2-9)-((7*x)/(x^2-9)) = 0

(5*x-5)/(x^2-9)-7*x*(x^2-9)^-1 = 0

(5*x-5)/(x^2-9)+(-7*x)/(x^2-9) = 0

5*x-7*x-5 = 0

-2*x-5 = 0

(-2*x-5)/(x^2-9) = 0

(-2*x-5)/(x^2-9) = 0 // * x^2-9

-2*x-5 = 0

-2*x-5 = 0 // + 5

-2*x = 5 // : -2

x = 5/(-2)

x = -5/2

x = -5/2

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